Question
Wed July 18, 2012 By:
 

two years ago, a man was five times as old as his son. two years later, his age will be 8 more than three times the age of the son. find the present ages of the man and his son.

Expert Reply
Wed July 18, 2012

Let present age of father be x and present age of son be y.

2 yrs ago:

x-2 = 5(y-2)                  ... (1)

2 yrs hence:

x+ 2= 8 + 3(y+2)           ... (2)

From (1), x = 5y - 8

Substitute the value of x in (2),

5y-8 +2 = 8+3y +6

2y = 20

y=10

So, x = 50 - 8 = 42

Present age of father = 42 yrs

Present age of son= 10 yrs

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