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Question
Mon October 22, 2012 By:

# Solve the following question:

Mon October 22, 2012

. E.M.F of each cell, E = 2.0 V
Terminal voltage of cell, V = 1.5 V
Let r' be the internal resistance of each cell. As the two cells are connected in parallel, so the total internal resistance say 'r' of the cells is given by
r = (r'/2)
Total external resistance R is given by
R = 4ohms
Using equation for internal resistance
r = [(E - V)/V]R
We have, r = [(2.0 - 1.5)/1.5]4 = (0.5/1.5)4 ohm = (4/3) ohms
So, internal resistance of each cell,
r' = 2r = (4
x 2)/3 = (8/3) = 2.666 ohm

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# A cell of emf E and internal resistance r is connected to two external resistance R1 and R2 and a perfect ammeter.The current in the circuit is measured in four different situation: (i)without any external resistance in the circuit (ii)with resistance R1 only (iii)with Ri and R2 in series combination (iv)with R1 and R2 in parallel combination The currents measured in the four cases are 0.42A,1.05A,1.4A and 4.2A,but not necessarily in that order.Identify the currents corresponding to the four cases mentioned above.

Thu November 24, 2016

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