Question
Fri July 06, 2012 By: Priyanshi Shrivastava

prove that

Expert Reply
Sat July 07, 2012
RHS = 1+cosA+sinA/1+cosA-sinA
on rationalising, we get,
= (1+cosA+sinA/1+cosA-sinA) (1+cosA+sinA/1+cosA+sinA)
= (1+cosA+sinA)2/(1+cosA)2-sin2A
On solving and factorising,
= (1+cosA) 2(1+sinA)/ (1+cosA)(2 cosA)
= 1+sinA/cosA
On rationalising,
= 1-sin2A/cosA(1-sinA)
= cosA/1-sinA = LHS
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