Question
Thu April 07, 2011 By: Saurabh Budholiya
 

How many gms of ferric sulphide will contain total number of atoms equal to avogadros number

Expert Reply
Fri April 08, 2011
Molecular weight 87.91 g/mol
 
So, 87.91 g of FeS will contain 6.022 X 1023  molecules of FeS.
 
As, one molecule of FeS has one atom of Fe and one atom of S, 87.91 g FeS will have  6.022 X 1023  atoms of Fe and  6.022 X 1023  atoms of S. But half amount of FeS will contain total atoms = Avagadro's number
 
But, 87.91/2 g of FeS will contain total atoms = 6.022 X 1023  .
 
So, 43.95 g of FeS will contain 6.022 X 1023 atoms total.
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