Question
Thu May 03, 2012 By:
 

for an ap show that tp+tp+2q=2tp+q

Expert Reply
Thu May 03, 2012
Let a be the first term and d be the common difference of the AP.
Now, tp + tp + 2q =
a + (p - 1)d + a + (p + 2q - 1)d
= 2a + 2(p + q - 1)d
= 2[a + (p + q - 1)d]
= 2tp + q
Hence, proved.
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