Question
Fri June 03, 2011 By:

Find the largest number that will divide 398,436 and 542 leaving remainder 7,11,15 respectively.

Expert Reply
Thu June 02, 2011

On dividing 398 by the required number, there is a remainder of 7. This means that 398 – 7 = 391 is exactly divisible by the required number. Similarly, 436 -11 = 425 and 542 – 15 = 527 are exactly divisible by the required number.

The HCF of two positive integers is the largest positive integer that divides both the integers.

So, the required number will be the HCF of 391, 425 and 527. And that can be found by using Euclid’s division algorithm.

425 = 391 x 1 + 34

391 = 34 x 11 + 17

34 = 17 x 2 + 0

Thus, HCF = 17

Hence, the required number is 17.

Related Questions
Wed October 26, 2016

please answer

Ask the Expert