Sun December 16, 2012 By: Arvind Bala
Consider a capacitor connected to a circuit where current flows,and a potential difference V equal to the emf of the cell is attained. Now i increase the distance between the capacitor, What are the changes happenning to the following:


Expert Reply
Tue January 22, 2013
As the distance between the capacitor plates is increased, the capacitance decreased as it is inversely propotional to the distance between the plates.
Since the external circuit remains same, the potential difference between the plates remain same as it is maintained due to the external emf.
The electric field decreases because it is inversely proportional to the distance between the plates.
the charge on the plates is given as Q=CV and since V remains same but C decreases thus Q decreases.
Ask the Expert