Question
Fri February 18, 2011 By: Ishaan Kumar

Bond Order

Expert Reply
Fri February 18, 2011
Dear Student
 
bond order = ½ (bonding electrons − antibonding electrons)
 
BO of N2 = 1/2(8-2)= 3

O2: KK(s2s)2 (s*2s)2 (s2pz)2 (p2px)2 (p2py)2 (p*2px)1(p*2py)1
 
Bond Order = 1/2(8-4)= 2


O2+: KK(s2s)2 (s*2s)2 (s2pz)2 (p2px)2 (p2py)2 (p*2px)2 (p*2py)
 
Bond Order = 1/2(8-3) = 2.5

O2-: KK(s2s)2 (s*2s)2 (s2pz)2 (p2px)2 (p2py)2 (p*2px)2 (p*2py)1
 
 Bond Order = 1/2 (8-5) =1.5

 
We hope that clarifies your query.
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