Request a call back

Join NOW to get access to exclusive study material for best results

Class 11-commerce TR JAIN AND VK OHRI Solutions Statistics for Economics Chapter 4 - Organisation of Data

Organisation of Data Exercise 75

Solution SAQ 1

ii. Data with cumulative frequencies:

Marks

No. of Students

Marks

No. of Students

Less than 29

0 +2 =2

More than 20

25

Less than 39

2 + 5 =7

More than 30

25 - 2 =23

Less than 49

7 + 8 =15

More than 40

23 - 5 =18

Less than 59

15 + 6 =21

More than 50

18 - 8 =10

Less than 69

21 + 4 =25

More than 60

10 - 6 =4

Solution SAQ 2

Data in the form of frequency distribution:

Solution SAQ 3

Individual series:

15

15

15

15

16

16

16

17

18

18

18

18

19

20

20

20

21

22

22

22

22

23

24

24

24

25

25

25

25

25

 

Cumulative frequency series:

Marks

No. of Students

Marks

No. of Students

Less than 15

0

More than 12

30

Less than 19

9 + 4 =13

More than 16

30 - 4 =26

Less than 23

13 + 9 =22

More than 20

26 - 9 =17

Less than 27

22 + 8 = 30

More than 24

17 - 9 =8

Solution SAQ 4

 

Exclusive frequency distribution:

Organisation of Data Exercise 76

Solution SAQ 5

Frequency distribution:

Solution SAQ 6

Given data can be written as:

Marks

Cumulative Frequency (c.f)

Less than 3

5

Less than 6

12

Less than 9

25

Less than 12

33

Simple frequency distribution:

Marks

Frequency (f)

0 - 3

5

3 - 6

7 (= 12 - 5)

6 - 9

13(= 25 - 12)

9 - 12

8(= 33 - 25)

 

∑f =33

Solution SAQ 7

Discrete series:

Solution SAQ 8

i. Frequency distribution:

Solution SAQ 9

Frequency distribution on exclusive basis:

Weight (in kg)

No. of students (f)

40 - 50

7

50 - 60

7

60 - 70

5

70 - 80

3

80 - 90

2

90 - 100

1

 

∑f = 25

 

Frequency distribution on inclusive basis: 

Weight (in kg)

No. of students (f)

40 - 50

9

51 - 61

6

62 - 72

6

73 - 83

2

84 - 94

2

95 - 105

0

 

∑f = 25

Organisation of Data Exercise 77

Solution SAQ 10

Lower limits and upper limits of class intervals are calculated using the following formula.

  

where m is mid value and i is the difference between mid-values.

 

Mid-value

Class-interval

Frequency (f)

5

0 - 10

2

15

10 - 20

8

25

20 - 30

15

35

30 - 40

12

45

40 - 50

7

55

50 - 60

6

 

 

∑f = 50

Solution SAQ 11

Lower limits and upper limits of class intervals are calculated using the following formula.

  

where m is mid value and i is the difference between mid-values.

 

Mid-value

Class-interval

Frequency (f)

12

9.5 - 14.5

1

17

14.5 - 19.5

5

22

19.5- 24.5

4

27

24.5 - 29.5

4

32

29.5 - 34.5

8

37

34.5 - 39.5

6

42

39.5 - 44.5

11

47

44.5 - 49.5

4

52

49.5 - 54.5

5

 

 

∑f = 48

Get Latest Study Material for Academic year 24-25 Click here
×