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# Class 11-commerce TR JAIN AND VK OHRI Solutions Statistics for Economics Chapter 4 - Organisation of Data

## Organisation of Data Exercise 75

### Solution SAQ 1

ii. Data with cumulative frequencies:

 Marks No. of Students Marks No. of Students Less than 29 0 +2 =2 More than 20 25 Less than 39 2 + 5 =7 More than 30 25 - 2 =23 Less than 49 7 + 8 =15 More than 40 23 - 5 =18 Less than 59 15 + 6 =21 More than 50 18 - 8 =10 Less than 69 21 + 4 =25 More than 60 10 - 6 =4

### Solution SAQ 2

Data in the form of frequency distribution:

### Solution SAQ 3

Individual series:

 15 15 15 15 16 16 16 17 18 18 18 18 19 20 20 20 21 22 22 22 22 23 24 24 24 25 25 25 25 25

Cumulative frequency series:

 Marks No. of Students Marks No. of Students Less than 15 0 More than 12 30 Less than 19 9 + 4 =13 More than 16 30 - 4 =26 Less than 23 13 + 9 =22 More than 20 26 - 9 =17 Less than 27 22 + 8 = 30 More than 24 17 - 9 =8

### Solution SAQ 4

Exclusive frequency distribution:

## Organisation of Data Exercise 76

### Solution SAQ 5

Frequency distribution:

### Solution SAQ 6

Given data can be written as:

 Marks Cumulative Frequency (c.f) Less than 3 5 Less than 6 12 Less than 9 25 Less than 12 33

Simple frequency distribution:

 Marks Frequency (f) 0 - 3 5 3 - 6 7 (= 12 - 5) 6 - 9 13(= 25 - 12) 9 - 12 8(= 33 - 25) ∑f =33

Discrete series:

### Solution SAQ 8

i. Frequency distribution:

### Solution SAQ 9

Frequency distribution on exclusive basis:

 Weight (in kg) No. of students (f) 40 - 50 7 50 - 60 7 60 - 70 5 70 - 80 3 80 - 90 2 90 - 100 1 ∑f = 25

Frequency distribution on inclusive basis:

 Weight (in kg) No. of students (f) 40 - 50 9 51 - 61 6 62 - 72 6 73 - 83 2 84 - 94 2 95 - 105 0 ∑f = 25

## Organisation of Data Exercise 77

### Solution SAQ 10

Lower limits and upper limits of class intervals are calculated using the following formula.

where m is mid value and i is the difference between mid-values.

 Mid-value Class-interval Frequency (f) 5 0 - 10 2 15 10 - 20 8 25 20 - 30 15 35 30 - 40 12 45 40 - 50 7 55 50 - 60 6 ∑f = 50

### Solution SAQ 11

Lower limits and upper limits of class intervals are calculated using the following formula.

where m is mid value and i is the difference between mid-values.

 Mid-value Class-interval Frequency (f) 12 9.5 - 14.5 1 17 14.5 - 19.5 5 22 19.5- 24.5 4 27 24.5 - 29.5 4 32 29.5 - 34.5 8 37 34.5 - 39.5 6 42 39.5 - 44.5 11 47 44.5 - 49.5 4 52 49.5 - 54.5 5 ∑f = 48