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R S Aggarwal and V Aggarwal Solution for Class 9 Mathematics Chapter 5 - Coordinate Geometry

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Our RS Aggarwal & V Agarwal Textbook Solutions are considered extremely helpful for solving the tough questions which are asked in the CBSE Class 9 board exam. TopperLearning Textbook Solutions are compiled by subject experts. Herein, you can find all the answers to the textbook questions for Chapter 5 - Coordinate Geometry.

All our solutions are created in accordance with the latest CBSE syllabus, and they are amended from time to time to provide the most relevant answers. Our free RS Aggarwal & V Agarwal Textbook Solutions for CBSE Class 9 Mathematics will strengthen your fundamentals in this chapter and will help you in your attempts to score more marks in the final examination. CBSE Class 9 students can refer to our solutions any time — while doing their homework and while preparing for the exam.

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Exercise/Page

R S Aggarwal and V Aggarwal Solution for Class 9 Mathematics Chapter 5 - Coordinate Geometry Page/Excercise MCQ

Solution 1

Correct option: (c)

Since, both the coordinates of given point are negative, it lies in Quadrant III. 

Solution 2

Correct option: (d)

  

Solution 3

Correct option: (b)

Since, x co-ordinate is negative and y co-ordinate is positive, the given point lies in Quadrant II.

Solution 4

Correct option: (c)

  

  

Solution 5

Correct option: (c)

  

  

Solution 6

Correct option: (c)

For point (-5, 3), the x co-ordinate is negative and the y co-ordinate is positive. Hence, it lies in Quadrant II.

For point (3, -5), the x co-ordinate is positive and the y co-ordinate is negative. Hence, it lies in Quadrant IV.

Solution 7

Correct option: (d)

Points (1, -1), (2, -2) and (4, -5) lie in Quadrant IV, but point (-3, -4) lies in Quadrant III.

Hence, all the given points do not lie in the same quadrant. 

Solution 8

Correct option: (d)

Point (0, -8) lies on y-axis as its x co-ordinate is 0. 

Solution 9

Correct option: (a)

Point (-7, 0) lies on negative direction of the x-axis as its x co-ordinate is negative and y co-ordinate is zero. 

Solution 10

Correct option: (b)

The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is (0, -5). 

Solution 11

Correct option: (c)

The ordinate (y co-ordinate) of every point on the x-axis is 0. 

Solution 12

Correct option: (b)

If the y-coordinate of a point is zero then this point always lies on the x-axis. 

Solution 13

Correct option: (b)

By plotting the given points, we find that figure OABC is a rectangle.

  

Solution 14

Correct option: (b)

Abscissa of A - Abscissa of B

= -2 - (-3)

= -2 + 3

= 1 

Solution 15

Correct option: (a)

The perpendicular distance of the point A(3, 4) from the y-axis is 3 units. 

Solution 16

Correct option: (b)

  

  

Solution 17

  

Solution 18

Correct option: (b)

If a point lies on y-axis, then its abscissa is 0.

Hence, the point whose ordinate is 3 and which lies on the y-axis is (0, 3). 

Solution 19

  

Solution 20

  

Solution 21

Correct option: (d)

The abscissa of point (0, 3) is 0. Hence, it lies on y-axis. 

Solution 22

Correct option: (c)

  

Clearly, ΔAOB is a right-angled triangle.

R S Aggarwal and V Aggarwal Solution for Class 9 Mathematics Chapter 5 - Coordinate Geometry Page/Excercise 5

Solution 1

The given points are plotted as follows:

  

Solution 2

Draw the perpendiculars from the AF, BG, CH, DI and EJ on the x-axis.

(1) The distance of A from the y-axis = OF = -6 units

     The distance of A from the x-axis = AF = 5 units

     Hence, the coordinate of A are (-6, 5)

(2)The distance of B from the y-axis = OG = 5 units

     The distance of B from the x-axis = BG = 4 units

     Hence, the coordinate of B are (5, 4)

(3)The distance of C from the y-axis = OH = -3 units

     The distance of C from the x-axis = HC = 2 units

     Hence, the coordinate of C are (-3, 2)

(4)The distance of D from the y-axis = OI = 2 units

     The distance of D from the x-axis = ID = -2 units

     Hence, the coordinate of D are (2, -2)

(5)The distance of E from the y-axis = OJ = -1 unit

     The distance of E from the x-axis = JE = -4 units

     Hence, the coordinate of E are (-1, -4)

Thus, the coordinates of A, B, C, D and E are respectively, A(-6,5), B(5,4), C(-3,2), D(2,-2) and E(-1,-4)

Solution 3

(i) (-6, 3):

 x co-ordinate is negative and y co-ordinate is positive.

 Hence, (-6, 3) lies in the 2nd Quadrant.

 

(ii) (-5, -3) :

 x co-ordinate and y co-ordinate both are negative.

 Hence, (-5, -3) lies in the 3rd Quadrant.

 

(iii) (11, 6):

  x co-ordinate and y co-ordinate both are positive.

  Hence, (11, 6) lies in the 1st Quadrant.

 

(iv) (1, -4):

 x co-ordinate is positive and y co-ordinate is negative.

  Hence, (1, -4) lies in the 4th Quadrant.

 

(v) (-7, -4):

 x co-ordinate and y co-ordinate both are negative.

 Hence, (-7, -4) lies in the 3rd Quadrant.

 

(vi) (4, -1):

 x co-ordinate is positive and y co-ordinate is negative.

 Hence, (4, -1) lies in the 4th Quadrant.

 

(vii) (-3, 8):

 x co-ordinate is negative and y co-ordinate is positive.

 Hence, (-3, 8) lies in the 2nd Quadrant.

 

(viii) (3, -8):

 x co-ordinate is positive and y co-ordinate is negative.

 Hence, (3, -8) lies in the 4th Quadrant. 

Solution 4

(i) (2, 0) lies on the x-axis as the co-ordinates of every point on the x-axis are of the form (x, 0).

(ii) (0, -5) lies on the y-axis as the co-ordinates of every point on the y-axis are of the form (0, y).

(iii) (-4, 0) lies on the x-axis as the co-ordinates of every point on the x-axis are of the form (x, 0).

(iv) (0, -1) lies on the y-axis as the co-ordinates of every point on the y-axis are of the form (0, y). 

Solution 5

The co-ordinates of every point on the X-axis are of the form (x, 0).

Hence, following points lie on the x-axis:

(ii) B(4, 0)  

(iv) D(-6, 0)

(vii) G(-1, 0) 

Solution 6

The given points are plotted on the graph paper as follows:

Solution 7

The given vertices of rectangle ABCD are plotted on graph paper as follows:

The coordinates of fourth vertex D are (3, 3)

Area of rectangle ABCD = Length × Breadth

= AB × BC

= 6 × 2 

= 12 square units

TopperLearning provides step-by-step solutions for each question in each chapter in the RS Aggarwal & V Aggarwal Textbook. Access the CBSE Class 9 Mathematics Chapter 5 - Coordinate Geometry for free. The questions have been solved by our subject matter experts to help you understand how to answer them. Our RS Aggarwal Solutions for class 9 will help you to study and revise the whole chapter, and you can easily clear your fundamentals in Chapter 5 - Coordinate Geometry now.

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