Class 11-commerce RD SHARMA Solutions Maths Chapter 5: Trigonometric Functions
Trigonometric Functions Exercise Ex. 5.1
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Solution 17
Solution 18
Solution 19
Solution 20
Solution 21
Solution 22
Solution 23
Solution 24
Solution 25
Solution 26(i)
Solution 26(ii)
Solution 26(iii)
Trigonometric Functions Exercise Ex. 5.2
Solution 1(i)
Solution 1(ii)
Solution 1(iii)
Solution 1(iv)
Solution 2
Solution 3
Solution 4
Solution 5
Trigonometric Functions Exercise Ex. 5.3
Solution 1(i)
Solution 1(ii)
Solution 1(iii)
Solution 1(iv)
Solution 1(v)
Solution 1(vi)
Solution 1(vii)
Solution 1(viii)
Solution 1(ix)
Solution 1(x)
Solution 1(xi)
Solution 1(xii)
Solution 1(xiii)
Solution 1(xiv)
Solution 2(i)
Solution 2(ii)
Solution 2(iii)
Solution 2(iv)
Solution 2(v)
Solution 2(vi)
Solution 2(vii)
Solution 3(i)
Solution 3(ii)
Solution 3(iii)
Solution 3(iv)
Solution 3(v)
Solution 4
Solution 5
Solution 6(i)
Solution 6(ii)
Solution 6(iii)
Solution 7
Solution 8(i)
Solution 8(ii)
Solution 9(i)
Solution 9(ii)
Solution 9(iii)
Solution 9(iv)
Solution 9(v)
Trigonometric Functions Exercise Ex. 5VSAQ
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
The maximum value for sin(x) is 1 for all x.
Solution 9
Solution 10
The radius of circular wire is 15 cm.
The circumference of circular wire is
.
The radius of loop is 120 cm.
The circumference of loop is
.
The circumference of a circle covers
all the quadrants of the circle i.e. the angle subtended by it at the centre is
.
The circular wire is cut and bent so as to lie along the circumstance of the loop.
So, circumference of circular wire covers
of
the circumference of the loop.
Therefore the angle subtended by the circular wire is
.
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
So
the least value of 
is 2.
Solution 16
Solution 17
