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Class 11-commerce RD SHARMA Solutions Maths Chapter 25: Parabola

Parabola Exercise Ex. 25.1

Solution 1(i)

Solution 1(iii)

Solution 1(ii)

Solution 1(iv)

Solution 2

 L a t u s space R e c t u m space equals L e n g t h space o f space p e r p e n d i c u l a r space f r o m space f o c u s space left parenthesis 2 comma 3 right parenthesis space o n space d i r e c t r i x space x minus 4 y plus 3 equals 0 equals 2 open vertical bar fraction numerator 2 minus 12 plus 3 over denominator square root of 1 plus 16 end root end fraction close vertical bar equals 2 open vertical bar fraction numerator minus 7 over denominator square root of 17 end fraction close vertical bar equals fraction numerator 14 over denominator square root of 17 end fraction

Solution 3(i)

Solution 3(ii)

Solution 3(iii)

Solution 3(iv)

Solution 3(v)

 
 
 
 
 
 

Solution 4(i)

Solution 4(ii)

Solution 4(iii)

Solution 4(iv)

Solution 4(v)

Solution 4(vi)

Solution 4(vii)

Solution 4(viii)

Solution 4(ix)

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

Solution 10

Solution 11

Solution 12

Solution 13

Solution 14

In given parabola

a=2

Given focal distance=a+x=4, so x=2

So points are (2, 4) and (2, -4)

Solution 15

Solution 16

 

Solution 17

 

Parabola Exercise Ex. 25VSAQ

Solution 1

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

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