RD SHARMA Solutions for Class 10 Maths Chapter 10 - Trigonometric Ratios
Chapter 10 - Trigonometric Ratios Exercise Ex. 10.1
In ABC by applying Pythagoras theorem
AC2 = AB2 + BC2
= (24)2 + (7)2
= 576 + 49
= 625
AC = = 25 cm
Given:
Chapter 10 - Trigonometric Ratios Exercise Ex. 10.2
Given: tan(A + B) = 1 and
Therefore,
A + B = 45o … (i)
A - B = 30o … (ii)
Adding the two equations, we get
Chapter 10 - Trigonometric Ratios Exercise Ex. 10.3
Given: ∠A = 90o
For a triangle ABC, ∠A + ∠B + ∠C = 90o
Using the identities
For a triangle ABC, ∠A + ∠B + ∠C = 90o
Given: tan 2A = cot(A - 18o)
As tan x = cot(90o - x), we have
cot(90o - 2A) = cot(A - 18o)
90o - 2A = A - 18o
3A = 108o
Therefore, A = 36o.
Chapter 10 - Trigonometric Ratios Exercise 10.56
So, the correct option is (a).
Chapter 10 - Trigonometric Ratios Exercise 10.57
So, the correct option is (d).
So, the correct option is (c).
So, the correct option is (b).
So, the correct option is (a).
So, the correct option is (b).
So, the correct option is (d).
Chapter 10 - Trigonometric Ratios Exercise 10.58
So, the correct option is (b).
So, the correct option is (d).
So, the correct option is (a).
Chapter 10 - Trigonometric Ratios Exercise 10.59
So, the correct option is (c).
Other Chapters for CBSE Class 10 Mathematics
Chapter 1- Real Numbers Chapter 2- Polynomials Chapter 3- Pairs of Linear Equations in Two Variables Chapter 4- Quadratic Equations Chapter 5- Arithmetic Progressions Chapter 6- Co-ordinate Geometry Chapter 7- Triangles Chapter 8- Circles Chapter 9- Constructions Chapter 11- Trigonometric Identities Chapter 12- Heights and Distances Chapter 13- Areas Related to Circles Chapter 14- Surface Areas and Volumes Chapter 15- Statistics Chapter 16- ProbabilityRD SHARMA Solutions for CBSE Class 10 Subjects
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