Class 9 R S AGGARWAL AND V AGGARWAL Solutions Maths Chapter 19 - Probability
Probability Exercise MCQ
Solution 1
Correct option: (d)
Total number of people = 645
Number of people having high school certificate = 516
Solution 2
Correct option: (c)
Total number of students = 11 + 15 + 8 + 6 = 40
Number of students having blood group AB = 8
Solution 3
Correct option: (d)
Total number of bulbs = 80
Number of bulbs having life of 1150 hours = 0
∴ Required probability = 0
Solution 4
Correct option: (c)
Total number of children = 364
Number of children who like to eat potato chips = 91
⇒ Number of children who do not like to eat potato chips = 364 - 91 = 273
Solution 5
Correct option: (b)
Total number of outcomes = 1000
Solution 6
Correct option: (b)
Total number of bulbs = 80
Solution 7
Correct option: (c)
Total number of students = 200
Number of students who does not like Sanskrit = 65
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Correct option: (c)
Total number of outcomes = 600
Probability Exercise Ex. 19
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Number of tests in which he gets more than60% marks =2
Total numbers of tests =6
Required probability
Solution 7
Solution 8
Solution 9
Solution 10
Total number of salt packets = 12
Number of packets containing more than 2 kg of salt = 5
Therefore,
Probability that the chosen packet contains more than 2 kg of salt
Solution 11
Total number of ball played = 30
Number of times boundary was hit = 6
⇒ Number of times boundary was not hit = 30 - 6 = 24
Therefore,
Probability that the batsman did not hit the boundary
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Solution 17
Total number of electric bulbs = 800
Number of defective bulbs = 36
⇒ Number of non-defective bulbs = 800 - 36 = 764
Hence, probability that the bulb chosen is non-defective
Solution 18
Fill in the blanks.
(i) Probability of an impossible event = 0
(ii) Probability of a sure event = 1
(iii) Let E be an event. Then, P(not E) = 1 - P(E)
(iv) P(E) + P(not E) = 1
(v) 0 ≤ P(E) ≤ 1