NCERT Solutions for Class 9 Physics Chapter 10 - Gravitation

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Chapter 10 - Gravitation Exercise 134

Solution 1

The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. The gravitational force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres.

Consider two objects of masses m1 and m2 and let the distance between their centres be r. The gravitational force of attraction (F) acting between them is given by the universal law of gravitation as:

Concept Insight -              Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

where, G is the universal gravitation constant given by:

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

Solution 2

Let M  be the mass of the Earth and m be the mass of an object on its surface. If R is the radius of the Earth, then according to the universal law of gravitation, the gravitational force (F) acting between the Earth and the object is given by the relation:

Concept Insight -

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
 

Chapter 10 - Gravitation Exercise 136

Solution 1

Gravity of the Earth attracts every object towards its centre. When an object is released from a height such that it falls towards the surface of the Earth under the influence of gravitational force alone, the motion of the object is called free fall.

Solution 2

During free fall of an object towards the earth, the magnitude of velocity of the falling object goes on increasing. This changing velocity produces acceleration in the object. This acceleration is known as acceleration due to gravity (g). Its value is given by 9.8 m/s2.

 
Concept Insight - 

The value of acceleration due to gravity changes from place to place but for most of the purposes it is taken to be 9.8 m/s2.

Chapter - Exercise

Solution 1

Chapter 10 - Gravitation Exercise 138

Solution 1

Let ME be the mass of the Earth and m be the mass of an object on the surface of the Earth. Let RE be the radius of the Earth. According to the universal law of gravitation, weight WE of the object on the surface of the Earth is given by,

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation 

Let MM and RM be the mass and radius of the Moon. Then, according to the universal law of gravitation, weight WM of the same object on the surface of the Moon is given by:

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

 Therefore, weight of an object on the moon is Ncert Solutions Cbse Class 9 Physics Chapter - Gravitationth of its weight on the Earth.

Concept Insight Gravitational force of the moon is Ncert Solutions Cbse Class 9 Physics Chapter - Gravitationth that of the earth.

Chapter 10 - Gravitation Exercise 141

Solution 1

It is difficult to hold a school bag having a thin strap because the pressure exerted on the shoulders is quite large. This is because the pressure is inversely proportional to the surface area on which the force acts. The smaller the surface area; the larger will be the pressure on the surface. In the case of a thin strap, the contact surface area is very small. Hence, the pressure exerted on the shoulders is very large.

 
Concept Insight - Pressure = Force/Area  

Solution 2

Whenever an object is immersed in a fluid, either partially or fully, it experiences an upward force by the fluid. This force is called buoyant force or upthrust and the property due to which a fluid exerts this upthrust on an object placed in it, is called buoyancy.

Solution 3

If the density of an object is more than the density of water, then it sinks in water. This is because the buoyant force acting on the object is less than the force of gravity acting on it. On the other hand, if the density of an object is less than the density of water, then it floats on the surface of water. This is because the buoyant force acting on the object is greater than the force of gravity acting on it.


Concept Insight -Density of an object is a key factor to decide whether it'll float or sink in a liquid.

Chapter 10 - Gravitation Exercise 142

Solution 1

When you weigh your body, an upward force (due to air) acts on it. This upward force is the buoyant force. As a result, the body gets pushed slightly upwards, causing the weighing machine to show a reading less than the actual value.


Concept Insight -The upthrust of air acting on the body reduces the weight of the body.

Solution 2

We know that true weight = apparent weight + upthrust. The cotton bag is heavier than the iron bar. This is due to the reason, that the bag of cotton which has more volume (as it has less density) than the iron bar (which has more density), experiences more upthrust due to air.

Concept Insight - Same mass does not necessarily means same buoyant force.

Chapter 10 - Gravitation Exercise 143

Solution 1

According to the universal law of gravitation, gravitational force (F) acting between two objects is inversely proportional to the square of the distance (r) between them, i.e.

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
Concept Insight - If distance r becomes r /2, then the gravitational force will be proportional to Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
 

Hence, if the distance is reduced to half, then the gravitational force would become four times.

Solution 2

It is true that gravitational force acts on all objects in proportion to their masses. But a heavy object does not fall faster than a light object. This is because of the reason that

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

As Force Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation Mass, therefore, acceleration is constant for a body of any mass.

 
Concept Insight - Acceleration due to gravity is constant for a heavy object as well as a light object.

Solution 3

According to the universal law of gravitation, gravitational force between two objects of masses M and m at a distance r from each other is given by:

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
Let mass of Earth be represented by M = 6 × 1024 kg

Let mass of the object be represented by m = 1 kg

Universal gravitational constant, G = 6.7 × 10-11 Nm2 kg-2

Since the object is on the surface of the Earth, r = radius of the Earth (R)

r = R = 6.4 × 106 m

 

Concept Insight -  Gravitational force,  Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
Solution 4

The Earth attracts the Moon with a force which is same as the force with which the moon attracts the Earth because according to Newton's third law of motion, force of action and reaction are always equal and opposite. So, the force of attraction of Earth on Moon is equal and opposite to the force of attraction of Moon on Earth.

Concept Insight - Action and reaction forces are always equal and opposite.

Solution 5

The Earth and the Moon experience equal gravitational forces from each other. However, the mass of the Earth is much larger than the mass of the Moon. Hence, it accelerates at a rate much lesser than the acceleration rate of the Moon towards the Earth. For this reason, we do not see the Earth moving towards the Moon.


Concept Insight - For the same force, an object with greater mass obtains less acceleration as compared to an object with lesser mass.

Chapter 10 - Gravitation Exercise 144

Solution 1

Weight of a body on the earth is given by:

W = m g

where,

m = Mass of the body

g = Acceleration due to gravity

The value of g is greater at poles than at the equator. Therefore, the same mass of gold weighs lesser at the equator than at the poles. Hence, Amit's friend will not agree with the weight of the gold bought.

Concept Insight - Acceleration due to gravity changes from place to place.  

Solution 2

A sheet of paper has more surface area than a crumpled ball of paper. So, the resistance offered by air to a sheet of paper falling through it is more than the resistance offered to a falling crumpled ball of paper. This decreases the speed of the sheet of paper and hence it falls slower than the crumpled ball.

Concept Insight - Amount of air resistance depends on the cross-sectional area of the object.
Solution 3

Weight = Mass × Acceleration

Acceleration due to gravity on earth, ge = 9.8 m/s2

Therefore, weight of a 10 kg object on the Earth = 10 × 9.8 = 98 N

Acceleration due to gravity on Moon, Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

Therefore, weight of the same object on the Moon = Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

Concept Insight Weight of an object on Moon =  Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation of the weight of the object on Earth

Solution 4

(i) For the upward motion of the ball, we use the equation:

v2 - u2 = 2 g h

where,

u = Initial velocity of the ball = 49 m/s (Given)

v = Final velocity of the ball = 0 (At the highest point)

h = Maximum height attained by the ball

g = Acceleration due to gravity = -9.8 m/s2 (Ball goes up)

Putting the values, we get

0 - (49)2 = 2 × (-9.8) × h

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

(ii) Let t be the time taken by the ball to reach the height 122.5 m, then to calculate t we use the following equation of motion:

v = u + g t

Putting the values, we get 

0 = 49 + (-9.8) × t

0 = 49 - 9.8 t

49 = 9.8 t

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

But, Time of ascent = Time of descent
 
Therefore, the total time taken by the ball to return = 5 + 5 = 10 s

Concept Insight - When a body is thrown vertically upwards, its velocity decreases, so the acceleration due to gravity g is taken as negative.

Solution 5

Initial velocity of the stone, u = 0

Final velocity of the stone, v = ?

Height of the tower, h = 19.6 m

Acceleration due to gravity, g = 9.8 ms-2

For a freely falling body:

v2 - u2 = 2 g h

v2 - 02 = 2 × 9.8 × 19.6

v2 = 19.6 × 19.6 = (19.6)

v2 = 384.16

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation 

v = 19.6 ms-1

Hence, the velocity of the stone just before touching the ground is 19.6 ms-1.

 

Concept Insight When a body is falling vertically downwards, its velocity increases, so the acceleration due to gravity g is taken as positive.

Solution 6

Given: 

Initial velocity of the stone, u = 40 m/s

Final velocity of the stone, v = 0 (At the highest point)

Maximum height reached by the stone, h = ?

Acceleration due to gravity, g = -10 ms-2 (Stone goes up)

Using the equation of motion:

v2 - u2 = 2 g h

0 - (40)2 = 2 × (-10) × h

0 - 1600 = - 20 h

-1600 = -20 h

1600 = 20 h

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

Thus, total distance covered by the stone during its upward and downward journey = 80 + 80 = 160 m

Net displacement of the stone during its upward and downward journey = 0 (since final position coincides with the initial position)

Concept Insight Distance is the length of the actual path covered by an object, while displacement is the shortest distance between the initial and final position of the object.

Solution 7

According to the universal law of gravitation, the force of attraction between the Earth and the Sun is given by:

 
Concept Insight- Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

where,

MSun = Mass of the Sun = 2 × 1030 kg

MEarth = Mass of the Earth = 6 × 1024 kg

R = Average distance between the Earth and the Sun = 1.5 × 1011 m

G = Universal gravitational constant = 6.7 × 10-11 Nm2 kg-2

Substituting the values, we get

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation 
Solution 8

Let the two stones meet after a time t.

(i) For the stone dropped from the top of the tower:

Initial velocity, u = 0

Let the displacement of the stone in time t from the top of the tower be s.

Acceleration due to gravity, g = 9.8 ms-2

From the equation of motion,

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

 

(ii) For the stone thrown upwards:

Initial velocity, u = 25 ms-1

Let the displacement of the stone from the ground in time t be s'.

Acceleration due to gravity, g = -9.8 ms-2

From the equation of motion,

Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation

 
The combined displacement (s + s') of both the stones at the meeting point is equal to the height of the tower 100 m.
 
From eqs. (1) and (2), we get,
s + s' = 4.9 t2 + 25 t - 4.9 t2
100 = 25 t
 
Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
In 4 s, the falling stone has covered a distance given by equation (1) as
s = 4.9 t2 = 4.9 × (4)2 = 78.4 m
 
Therefore, the stones will meet after 4 s at a height (100 - 78.4) = 21.6 m from the ground. 

Concept Insight Choose the equation of motion wisely to minimize the number of steps in calculations.

Solution 9
(a) Concept Insight - Time of ascent is equal to the time of descent.

The ball takes a total of 6 s for its upward and downward journey.

Hence, it has taken 3 s to attain the maximum height.

Let the initial velocity of the ball be u.

Final velocity of the ball at the maximum height, v = 0

Acceleration due to gravity, g = -9.8 ms-2

From the equation of motion, v = u + gt, we get,

0 = u + (-9.8) × 3

0 = u - 29.4

u = 29.4 ms-1

Hence, the ball was thrown upwards with a velocity of 29.4 ms -1.

 

(b) Let the maximum height attained by the ball be h.

Initial velocity during the upward journey, u = 29.4 ms -1

Final velocity, v = 0

Acceleration due to gravity, g = -9.8 m s -2

Concept Insight Choose the equation of motion wisely to minimize the number of steps in calculations.

From the equation of motion, Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation 
h = 44.1 m
 
 
(c) Ball attains the maximum height after 3 s. After attaining this height, it will start falling downwards.

In this case,

Initial velocity, u = 0

Position of the ball after 4 s of the throw is given by its position during the downward journey in 4 s - 3 s = 1 s.

Concept Insight - Choose the equation of motion wisely to minimize the number of steps in calculations.
 
From the equation of motion,  Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation, we get,
Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
 
Total height = 44.1 m

This means that the ball is 39.2 m (44.1 m - 4.9 m) above the ground after 4 seconds.

Solution 10
According to the universal law of gravitation, the force of gravitation between two objects is given by:
 
Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
(i) F is directly proportional to the product of masses of the objects. If the mass of one object is doubled, then the gravitational force will also get doubled.

(ii) F is inversely proportional to the square of the distance between the objects. If the distance is doubled, then the gravitational force becomes one-fourth of its original value.

Similarly, if the distance is tripled, then the gravitational force becomes one-ninth of its original value.

(iii) F is directly proportional to the product of masses of the objects. If the masses of both the objects are doubled, then the gravitational force becomes four times the original value.

Solution 11

The universal law of gravitation is important because it accounts for the force that binds us to the Earth, motion of planets around the Sun, motion of the Moon and other artificial satellites around the Earth, tides due to the Moon and the Sun and many other phenomena. 

Solution 12

When objects fall towards the Earth under the effect of gravitational force alone, then they are said to be in free fall.  This force produces a uniform acceleration in the objects, which is called acceleration of free fall or acceleration due to gravity. Its value is 9.8 m/s2.

Concept Insight - The value of acceleration of free fall is 9.8 m/s2, which is constant for all objects (irrespective of their masses).
Solution 13

Gravitational force between the Earth and an object is known as Earth's gravity or weight of the object.

Chapter 10 - Gravitation Exercise 145

Solution 1
An object immersed in a liquid experiences buoyant force in the vertically upward direction, i.e., in a direction opposite to the weight of the object.
Solution 2

In case of a block of plastic, the upward buoyant force is greater than the weight of the object. The large buoyant force on the block is due to its density being smaller than that of water. Due to the larger buoyant force, the block of plastic comes up when released under water.

Concept Insight - A body floats when its weight is lesser than the upward buoyant force acting on it. 

Solution 3

If the density of an object is more than the density of a liquid, then it sinks in the liquid. On the other hand, if the density of an object is less than the density of a liquid, then it floats on the surface of the liquid.

Here, density of the substance  Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
 
The density of the substance is more than the density of water (1 g cm-3). Hence, the substance will sink in water.
 
Concept Insight - Density of an object is a key factor in deciding whether the object will sink or float.
Solution 4
Ncert Solutions Cbse Class 9 Physics Chapter - Gravitation
The density of the substance is more than the density of water (1 g cm-3). Hence, it will sink in water.

As the packet is fully submerged in water,

Mass of water displaced by the packet = volume of the packet x density of water

                                                    = 350 cm3 × 1 g/cm3 = 350 g

Concept Insight - Density of an object is a key factor in deciding whether the object will sink or float.