NCERT Solutions for Class 12-science Physics Chapter 3 - Current Electricity
Updated NCERT Textbook Solutions Coming Soon!
Chapter 3 - Current Electricity Exercise 127
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Chapter 3 - Current Electricity Exercise 128
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Chapter 3 - Current Electricity Exercise 129
Solution 15
Solution 16
Solution 17
Solution 18
Solution 19
Solution 20
Chapter 3 - Current Electricity Exercise 130
Solution 21
Solution 22
(d) The method would not work if the driver cell of potentiometer had an emf of 1.0 V instead of 2.0 V. This is because if the emf of the driver cell of the potentiometer is less than the emf of the cell, then there would be no balance point on wire.
(e) The circuit would not work well for determining an extremelV small emf. As the circuit would be unstable, the balance point would be close to end A. Hence, there would be a large percentage of error
The given circuit can be modified if a series resistance is connected with the wire AB. The potential drop across AB is slightly greater than the emf measured. The percentage error would be small
Chapter 3 - Current Electricity Exercise 131
Solution 23
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change