# NCERT Solutions for Class 10 Maths Chapter 10 - Circles

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## Chapter 10 - Circles Exercise Ex. 10.1

Solution 1 Solution 2 Solution 3  Solution 4 ## Chapter 10 - Circles Exercise Ex. 10.2

Solution 1 Solution 2 Solution 3    Solution 4 Solution 5 Solution 6 Solution 7  Solution 8 Solution 9  Solution 10 Solution 11

Since, ABCD is a parallelogram,

AB = CD                                                                (i) Now, it can be observed that:

DR = DS                 (tangents on circle from point D)

CR = CQ                 (tangents on circle from point C)

BP = BQ                 (tangents on circle from point B)

AP = AS                 (tangents on circle from point A)

Adding all the above four equations,

DR + CR + BP + AP = DS + CQ + BQ + AS

(DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)

CD + AB = AD + BC                                            (iii)

From equation (i) (ii)  and (ii):

2AB = 2BC

AB = BC

AB = BC = CD = DA

Hence, ABCD is a rhombus.

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