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Class 8 MAHARASHTRA STATE TEXTBOOK BUREAU Solutions Maths Chapter 2: Parallel lines and transversals

Parallel lines and transversals Exercise Ex. 2.1

Solution 1

By the definition of corresponding angles, a pair of angles is in the same direction and the other arms are on the same side of the transversal.

Hence, from the diagram,

(1) ∠ p and w

(2) ∠ q and x

(3) ∠ r and y

(4) ∠ s and z

By definition of alternate interior angles, a pair of angles which are at the inner side of given lines and on the opposite side of the transversal

Hence, from the diagram,

(5) s and x

(6) ∠ w and ∠ r 

Solution 2(1)

By definition of interior alternate angles, a pair of angles which are at the inner side of lines and on the opposite side of transversal.

Hence, from the diagram,

c and e

b and h

Solution 2(2)

By the definition of corresponding angles, a pair of angles which are in the same direction and the other arms are on the same side of the transversal.

Hence, from the diagram,

a and e

c and g

b and f

d and h

Solution 2(3)

By the definition of interior angles, a pair of angles on the same side of the transversal and inside the given lines is called a pair of interior angles.

Hence, from the diagram,

c and h

b and e

Parallel lines and transversals Exercise Ex. 2.2

Solution 1(1)

From the diagram,

Line m || line n and p is a transversal where 3x and x are interior angles and sum of interior angles is 180˚.

3x + x = 180˚

4x = 180˚

x = 45˚

Solution 1(2)

Name the remaining angles and points as below in the diagram.

  

From the diagram,

Line a || line b and line l is a transversal.

PQT = QTR = 4x (Alternate angles)

QTR + 2x = 180˚ (Linear pair of angles)

4x + 2x = 180˚

6x = 180˚

x = 30˚

Solution 2

Name the remaining angles and points as below in the diagram.

  

From the diagram,

Line p || line q, line t and s are transversals.

ABC = 40˚

ABC + CBF = 180˚……(Linear pair of angles)

40˚ + CBF = 180˚

CBF = 180˚ ‒ 40˚

CBF = 140˚

CBF = x = 140˚…….(Corresponding angles)

 

HGJ = 70˚

HGJ + JGF = 180˚……..(Linear pair of angles)

70˚ + JGF = 180˚

JGF = 180˚ ‒ 70˚

JGF = 110˚

JGF = y = 110˚……(Corresponding angles)

 

x = 140˚, y = 110˚

Solution 3

Name the remaining angles and points as below in the diagram.

  

TYJ + VJY = 180˚………….(Interior angles)

80˚ + VJY = 180˚

VJY = 180˚ ‒ 80˚

VJY = 100˚

VJY = DJK = a = 100˚…..(Vertically opposite angles)

 

a + JDE = 180˚………….(Interior angles)

100˚ + JDE = 180˚

JDE = 180˚ ‒ 100˚

JDE = 80˚

JDE = b = 80˚………(Vertically opposite angles)

 

b = c = 80˚………….(Corresponding angles)

a = 100˚, b = c = 80˚

Solution 4

From the diagram,

Line a and line b are parallel.

Line l is a transversal.

 

x = 105˚……………..(Corresponding angles)

 

x = y = 105˚……….(Vertically opposite angles)

 

105˚ + z = 180˚………(Linear pair of angles)

z = 180˚ ‒ 105˚

z = 75˚

Solution 5

Name the remaining angles and points as below in the diagram.

 

  

Line p || line l || line q where BC is transversal

Consider, line p || line l

ABC = 40˚

ABC = BCE = 40˚…..…(i) (alternate angles)

 

Consider, line l || line q where CD is transversal

CDF = DCE = 30˚….…(ii) (Alternate angles)

 

x = BCE + DCE = 40˚ + 30˚ = 70˚

Parallel lines and transversals Exercise Ex. 2.3

Solution 1

Steps of Construction:

1. Draw line l.

2. Take a point A outside the line l.

3. Draw a seg AP line l. 

4. Take another point Q on the line l.

5. Draw seg QR line l where l(AP) = l(RQ)

6. The line n passing through the point A and R is parallel to the line l.

 

  

Solution 2

Steps of construction:

1. Draw line l.

2. Take a point T outside the line l.

3. Draw a seg TA line l.

4. Take the point B, draw seg BC line l such that l(TA) = l(CB)

5. The line t passing through the point T and C is parallel to the line l.

  

Solution 3

Steps of construction:

1. Draw line m.

2. Take two points X and Y on the line m.

3. Draw perpendicular to the line m from points X and Y.

4. On the perpendicular lines take point A and B at a distance of 4 cm from X and Y respectively.

5. Draw line n.

6. Line n

7. Line n is a line parallel to the line l at a distance 4 cm