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Class 8 MAHARASHTRA STATE TEXTBOOK BUREAU Solutions Maths Chapter 13: Congruence of triangles

Congruence of triangles Exercise Ex. 13.1

Solution 1

(i)

 

In ∆ WXZ and ∆ WYZ 

 

WX ≅ WY Given

XWZ ≅ YWZ Given

WZ ≅ WZ Common side

 

By Side-Angle-Side test ∆ WXZ and ∆ WYZ are congruent.

WXZ WYZ

 

(ii)

 

In ∆ KJI and ∆ LJI

 

KI ≅ LI Given

JI ≅ JI Common side and hypotenuse

IJK ≅ IJL Each angle is 90˚

By hypotenuse side test  ∆ KJI and ∆ LJI are congruent

KJI LJI

 

(iii)

In ∆ EFG and ∆ EGH

EH ≅ GF Given

HG ≅ EF Given

EG ≅ EG Common side

By SSS test ∆ EFG and ∆ FGH are congruent

EFG GHE

 

(iv)

 

In ∆ SMA and ∆ TPO

MSA ≅ POT Given

SM ≅ PO Given

AMS ≅ OPT Given

By ASA test ∆ SMA and ∆ TPO are congruent.

SMA OPT

 

(v)

 

In ∆ TNS and ∆ TNM

TM ≅ TS Given

MTN ≅ STN Given

TMN ≅ TNS Given

By SAA test ∆ TNS and ∆ TNM are congruent

TNS TNM

Congruence of triangles Exercise Ex. 13.2

Solution 1

(1)

In ∆ MBT and ∆ TBM

MS ≅ BT Given

MST ≅ MBT Right angle

MT ≅ MT Common side

∆ MBT TBM by hypotenuse side test

Side ST ≅ side BM

SMT ≅ BTM

STM ≅ BMT

 

(2)

 

In ∆ PQR and ∆ TSR

QR ≅ SR Given

PR ≅ TR Given

PRQ TRS Vertically opposite angles 

By SAS test ∆ PQR and ∆ TSR triangle are congruent

 

∆ PQR ≅ ∆ TSR 

Side PQ ≅ side TS

RPQ ≅ RTS, PQR ≅ TSR

 

(3)

In ∆ HCD and ∆ FCD

DC ≅ DC Common side

DHC ≅ DFC Given

HCD ≅ FCD Given

By SAA test ∆ HCD ≅ ∆ FCD are congruent

Side HC ≅ side FC

HDC ≅ FDC

Side HD ≅ side FD

Solution 2

In AAS test we need one side to be congruent and one angles on the line and other is opposite to the line.

Hence, either

DAB =  ECB and ABD =  CBE 

OR 

ADB =  CEB and ABD =  CBE