MAHARASHTRA Class 10: Pythagoras Theorem and Its Converse Videos | Application problems on Pythagoras theorem

∆ABC is an isosceles right-angled triangle, AC = CB,

non-opposite to ∠C = 90^o. AB2 = AC² + CB² AB2 = 6² + 6² AB = 6√2 

By Pythagoras theorem, hyptonenuse² = base² + perpendicular² = (4√2)² + (4√2)² = 8

AB² = 2AC²

AB² = AC² + AC²

AB² = AC² + CB² … (AC = CB)∆ABC is an isosceles right-angled triangle,

AC = CB, non-opposite to ∠C = 90^o.