Class 11-science H C VERMA Solutions Physics Chapter 22 - Photometry
Photometry Exercise 455
Solution 1
Solution 2
Radiant energy should be same so as to get equally intense lines. Thus,
Solution 3
According to figure:
a) Relatives luminosity of wavelength 480nm is 0.14
b) Relatives luminosity of wavelength 520nm is 0.68
c) Relatives luminosity of wavelength 580nm is 0.92
d) Relatives luminosity of wavelength 600nm is 0.66
Solution 4
Relative luminocity is given as:
Radiant flux is:
Solution 5
Luminous flux is given as:
And relative luminosity is given as:
Solution 6
Total radiant flux is given as:
Total Luminous flux is given as:
Luminous efficiency is given as:
(Approx.)
Solution 7
Total luminous efficiency is given as:
(Approx.)
Solution 8
Solid angle is given as 4
and
Luminous flux is given as:
And luminous intensity=
Solution 9
Luminous intensity is given as:
And Illuminance is given as:
Solution 10
Luminous intensity is given as:
And
Solution 11
Illumiance is given as:
And
Solution 12
Now
Thus illuminance will not change.
Solution 13
Illuminance is given as:
For condition of maximum illuminance:
Solution 14
Also,
Solution 15
and
and
Solution 16
Intensity of illumination is given as:
