Class 12-science H C VERMA Solutions Physics Chapter 22 - X-Rays
X-Rays Exercise 395
Solution 1
(a) Energy , E=
= 12.4 keV
(b) Frequency,
(c) Momentum,
Solution 2
We know,
Solution 3
We know,
= 41.4pm
Solution 4
Thus,
= 12.4kV
Now,
Maximum Energy, 
E = 2 × 
J
Solution 5
We know,
= 15.5keV
Solution 6
We know, 
And 
% change in wavelength = 
=
= 0.99 = 1%
Solution 7
Energy is given as:
Now electric field 
= 27.6kV/m
Solution 8
Now,
Also Potential difference,
V = 15.93 kV
Solution 9
We know,
Solution 10
We know,
Solution 11
Energy utilized is given as:
And Also 
Now, energy is
= 8400 eV
And
Now, energy is
= 2520 eV
And 
Solution 12
We Know,
Now,
Solution 13
Energy 
= 3450eV
Energy required to ionize is given as 16eV.
Thus, energy needed to knock out an electron from K -shell of argon atom is:
E = 3450 + 16
Solution 14
In case of Aluminium:
Now according to Moseley's Law
)
Taking ratio of (1) and (2) and solve if we get
b = 1.395
and
Now in case of iron
And also 
= 198pm
Solution 15
Energy is given as:
By Moseley's law
(Where a = 5×107, b = 1.37) (from question 14)
z = 20.15
z ≈ 20
Solution 16
We know
And 
Solution 17
La (Z=57)
Also Cu (z = 29)
= 28a ___________(2)
Dividing (1) and (2) we get
Solution 18
We know,
Subtracting equation (2) from (1) we get
And
Solution 19
We know,
Now,
And also 
Solution 20
We know,
And K∝ = fh
Also,
And 
Solution 21
Energy of electrons is:
E = ev
Where v is potential required for K series emission
This amount of energy = 
∴ Maximum potential difference is 11.3 kV
Solution 22
We know,
K.E of one e = eV
∴ Total K.E is:
= 400J
(a) Power entitled.
= 4W
(b) Heat Produced,
H = 400 - 4
= 396 J
Solution 23
And
X-Rays Exercise 396
Solution 24
We know
Z = 29.66 ≈30
Z = 28.55 ≈29
Z = 25.6 ≈26
Solution 25
Heat Energy = 
And Momentum 
Now,
Momentum of Photon = momentum of atom
And Recoil Energy 
Solution 26
We Know,
Also
And
Now Slopes are same, thus
Solution 27
We Know,
