Tue February 26, 2013 By: Ankit Rao

PQ is the chord of length 8 cm of a circle of radii 5 cm. The tangents at P and Q intersect at a point T. Find the length TP. Please give the solution in a simpler way.

Expert Reply
Wed February 27, 2013

Given, PQ is the chord of the circle and PT and QT are the tangents drawn at the end points of the chord PQ. PQ = 8cm and OP = 5cm.

Drawa OM perpendicular PQ and join OT

? PM = RM = 8/2 cm = 4 cm  (Perpendicular from the centre of the circle to a chord bisect the chord)

Now in triangle OMP


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