Question
Sat September 12, 2009 By: Vivek Venkatraman

please tell

Expert Reply
Sun September 13, 2009

Assume,

L = Length of the wire,

A = Cross sectional area of the wire,

ρ = Resistivity of the wire,

R = Resistance of the wire,

R = ρL/A

R' =  Resistance of 1 part = (ρL)/(5A)

1/Req = 5(1/R') = 5 (5A)/(ρL)

1/Req = (25A)/(ρL)

Req = (ρL)/(25A)

R/Req = 25

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