Question
Wed August 08, 2012 By:

Integrate sin 4x/sin 2x

Expert Reply
Wed August 08, 2012
Integral (sin 4x/sin 2x) dx
Integral (2sin 2x cos 2x /sin 2x) dx            [Using the formula: sin 2x = 2 sinx cosx] 
= Integral (2cos 2x) dx
= 2 * 1/2 * (sin2x) + C
= sin2x + C

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