Question
Sun February 05, 2012 By:

if p,q,r are rational numbers and p not equal to q not equal to r, then roots of the eqation (psquare-qsquare)xsquare-(qsquare-rsquare)x+(rsquare-psquare)=0 are wat?

Expert Reply
Sun February 05, 2012
Here we can see that sum of coefficients  a + b + c = 0
So b2 = (a + c)  ,   D = b2 - 4ac = (a - c)  =   (2p2 - r2 - q2)2
So roots are (-b +- root(D))/2a
= -1 , (p2 - r2 )/(p2 - q2)
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