Tue August 21, 2012 By:

A ball thrown up is caught by the thrower after 4s. How high did it go and with what velocity was it thrown? how far below its heighest point was it 3 s after start?

Expert Reply
Thu August 23, 2012
the time taken to move upward=time taken to move downwad
so the time taken by the stone to come down from the highest point=2 s
so from 2 nd equation of motuion,as it was moving down: 0+1/2 gt2=h
   h=5x2x2=20 m
so ut-1/2 g t2=20  while moving up
ie the distance it covered in t=1 sec from the highest point:h=5t2=5m
Related Questions
Fri August 11, 2017

Q.solve question 18

Mon August 07, 2017

plz ans the question

Home Work Help