Question
Fri March 30, 2012 By: Sruthi Sreekumar
The given question is the second question of Topper online test.

‘1’ is a zero of the polynomial P(a) = x2a2 - 2xa + 3x - 2 . Then x = ______

Expert Reply
Fri March 30, 2012
The correct solution of this question is given below:

Here, P(a) = x2a2 - 2xa + 3x - 2

1 is a zero of P(a), so P(1) = 0

Therefore, x212 - 2x.1 + 3x - 2 = 0

x2 + x - 2 = 0

(x + 2)(x - 1) = 0

x = -2, 1

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