The heat of combustion of benzene at constant volume was found to be 3263.9 kj/mol at 25 celcius calculate the heat of combustion of benzene in kj at constant pressure?
Asked by Arun Mathew
1st January 2013,
6:53 PM
Answered by Expert
Answer:
Given : Â ?E = Heat of combustion at constant volume= – 3263.9 kJ mol–1
T = 298K
R = 8.314 Jk–1Â mol–1
Â
To Find : Â ?H = Heat of combustion at constantpressure.
Â
Formula : Â ?H = ?E + ?nRT
Â
The required thermo chemical equation for thecombustion of benzene is
Â
C6H6Â +Â 152Â O2(g) Â -------> 6CO2(g)Â +3H2O(l)
Â
Â
SO, ?n = no. of moles of gaseous products– no. of moles of gaseous reactants= 6 – (15/2)= – 1.5
Â
?H = – 3263.9 + [(– 1.5) × 8.314 × 10–3Â × 298]= – 3263.9 – 3.71635= – 3267.6 kJ mol–1
Answered by Expert
2nd January 2013,
10:36 AM
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