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Asked by sakshisingh3124 30th June 2018, 9:35 PM
Answered by Expert
Answer:
begin mathsize 16px style let space PM space equals straight x
increment PMQ
tan space straight theta equals PQ over PM equals straight h over straight x................. left parenthesis 1 right parenthesis
increment PMR
tan space 2 straight theta equals PR over PM equals fraction numerator 3 straight h over denominator straight x end fraction................. left parenthesis 2 right parenthesis
from space 1 space and space 2
tan space 2 straight theta equals space 3 space tan space straight theta
fraction numerator 2 tanθ over denominator 1 minus tan squared straight theta end fraction equals 3 space tan space straight theta
fraction numerator 2 over denominator 1 minus tan squared straight theta end fraction equals 3
fraction numerator 2 over denominator 1 minus begin display style straight h squared over straight x squared end style end fraction equals 3
let space straight h over straight x equals straight t
2 equals 3 minus 3 straight t squared........... left parenthesis 3 right parenthesis
3 straight t squared equals 1
straight t equals straight h over straight x equals fraction numerator 1 over denominator square root of 3 end fraction

end style
Answered by Expert 3rd July 2018, 12:14 PM
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