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sir please answer

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Asked by minipkda 23rd May 2018, 10:23 PM
Answered by Expert
Answer:
Option (1) is correct.
 
space space space space space space space space space space space space space space space space space space space space space space straight A subscript open parentheses straight g close parentheses end subscript space rightwards arrow space straight B subscript open parentheses straight g close parentheses end subscript space plus space straight C subscript open parentheses straight s close parentheses end subscript
At space straight t equals space 0 space space space space space space space space space space space straight a space space space space space space space space space space space 0 space space space space space space space 0

At space straight t equals space straight t space space space space space space space space straight a minus straight x space space space space space space space space space straight x space space space space space space space space space space space straight x

therefore kt equals space 2.303 log fraction numerator straight a over denominator open parentheses straight a minus straight x close parentheses end fraction

As
straight a proportional to space straight P subscript 1
straight a minus straight x space plus space straight x plus space straight x space proportional to space straight P subscript 2

2 space straight P subscript 1 minus space straight P subscript 2 space proportional to space 2 straight a minus open parentheses straight a minus straight x close parentheses

therefore space space kt space equals space 2.303 log open parentheses fraction numerator space straight P subscript 1 over denominator 2 space straight P subscript 1 minus space straight P subscript 2 end fraction close parentheses
Answered by Expert 25th May 2018, 4:51 PM
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