ICSE Class 6 Answered
Question is in the image.
Asked by ploganathan9 | 19 Dec, 2019, 05:16: PM
Expert Answer
A boy is sitting at a distance of 1.5 m from one end.
Plank of see-saw is 5 m long.
The fulcrum of the see saw will be exactly at centre of plank i.e. 2.5 m
Thus, load arm is 2.5 - 1.5 = 1m
Thus,
Load arm x load = effort arm x effort
1 x 40 = EA x 25
Thus,
EA = 1.6 m
Thus, the distance at which a girl must sit from other end is = 2.5 - Effort arm = 2.5 - 1.6 = 0.9 m
Answered by Shiwani Sawant | 19 Dec, 2019, 06:03: PM
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