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Home / Doubts and Solutions/JEE/Mathematics

ques no41

Asked by chandanbr6004 30th November 2017, 9:48 PM
Answered by Expert
Answer:
begin mathsize 16px style the space given space terms space are space expansion space of space open parentheses 1 minus fraction numerator 2 straight x over denominator 1 plus straight x end fraction close parentheses to the power of negative straight n end exponent equals open parentheses fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction close parentheses to the power of negative straight n end exponent equals open parentheses fraction numerator 1 plus straight x over denominator 1 minus straight x end fraction close parentheses to the power of straight n end style
Answered by Expert 2nd December 2017, 7:58 PM
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