JEE Plances Class Answered

Que 10 and 11

Asked by Umesh | 25 Oct, 2017, 16:45: PM

Expert Answer

Question 11)

Let the hieght of tower be H=AB

Normal at point C bisect the 90 degree angle

therefore angle ACB = CAB = 45 degree because tower is at right angle with ground.

tan theta equals fraction numerator A B over denominator C B end fraction

(Angle ACB)

tan space 45 space equals space H over 60

H = 60 m

Note:- Please question other question separately. Only one question at a time can be answered.

Answered by Gajendra | 05 Dec, 2017, 19:17: PM

Answered Unanswered My Questions My Answers

Please Login or Sign up to continue!