JEE Plances Class Answered
Q no. 10
Asked by hariom2083 | 28 Jul, 2018, 02:10: AM
Expert Answer
In figure, acceleration vector and resolving components of that vector are shown.
The combined system of block-A and block-B moves parallel to inclined plane with acceleration g×sinθ
hence displacement in 1 s after releasing the block = (1/2)×(g×sinθ)×12 = ( g×sinθ ) / 2
Answered by Thiyagarajan K | 28 Jul, 2018, 23:49: PM
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