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Asked by Arushi Juyal 16th December 2017, 7:27 AM
Answered by Expert
F- is already negatively charged and its octet is complete hence it is neutral, so eliminate that  
Na is electropositive instead of accepting it will lose electrons, hence it is no incentive to add electrons, eliminate this too
Now between O and O-,
O has the highest affinity towards electrons than O-.
Hence O is the correct answer.
Answered by Expert 17th December 2017, 11:26 AM
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