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Home / Doubts and Solutions/ICSE/Class 11 Science/Chemistry

Please solve it

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Asked by nishabr7 31st August 2020, 10:08 PM
Answered by Expert
Answer:
Let's calculate oxidation number of N in each compound-
 
In space NH subscript 3 straight x plus 3 left parenthesis plus 1 right parenthesis equals 0 straight x equals negative 3 In space NO subscript 2 straight x plus 2 left parenthesis negative 2 right parenthesis equals negative 1 straight x equals 3 In space thin space NO straight x plus left parenthesis negative 2 right parenthesis equals 0 straight x equals 2 In space straight N subscript 2 straight H subscript 4 2 straight x plus 4 left parenthesis plus 1 right parenthesis equals 0 straight x equals negative 2 In space HN subscript 3 1 plus 3 straight x equals 0 straight x equals negative 1 third In space NO subscript 3 superscript minus straight x plus 3 left parenthesis negative 2 right parenthesis equals negative 1 straight x equals plus 5 So comma space order space of space oxidation space number space of space straight N NH subscript 3 space less than space straight N subscript 2 straight H subscript 4 less than straight H subscript 3 straight N space less than NO less than space NO subscript 2 less than space NO subscript 3 superscript minus
Answered by Expert 1st September 2020, 10:16 AM
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