CBSE XI Science Chemistry Redox Reactions
sir,here is my question on oxidation number
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what is oxidation state and how do you find it?
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Could you just share the link of the video lecture of oxidation number?
CBSE XII Science Chemistry The d-Block and f-Block Elements
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3) give the disproportionation reaction of
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CBSE XI Science Chemistry Redox Reactions
Give the oxidation number of all elements in CH3COOH? In my book the oxidation number of oxygen in this compound is -1? How
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Find the difference in the oxidation numbernumbers present of the two types of sulphur present in Na2S4O6 [sodium - 2 sulphur - 4 oxygen - 6]. (Hint :- sulphur-sulphur linkages present)
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Plz solve it step by step
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Pls solve.
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Equivalent weight is
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The incorrect order of decreasing oxidation number of S in compounds is: H2 S2 O7 > Na2 S4 O6 > Na2 S2 O3 > S8 H2 S O5 > H2 S O3 > S Cl2 > H2 S S O3 > S O2 > S8 > H2 S H2 S O4 > S O2 > H2 S > H2 S2 O8
CBSE XI Science Chemistry Redox Reactions
(i) Balance the following equations by oxidation number method:
(1) Cu + HNO3 → Cu (NO3)2 + NO2 + H2O)
(2) K2Cr2O7 + HCl → KCl + CrCl3 + H2O + Cl2
(ii) Give reasons for the following:
(1) HNO3 acts only as an oxidising agent while HNO2 can act both as a
reducing agent and an oxidising agent.
(2) Chlorine liberates iodine from KI solution.
How will you convert the following? (Give balanced equation.)
(1) Sodium acetate to methane
Find the oxidation number of:
(1) S in Na2S4 O6
2) S in
(1) Cu + HNO3 → Cu (NO3)2 + NO2 + H2O)
(2) K2Cr2O7 + HCl → KCl + CrCl3 + H2O + Cl2
(ii) Give reasons for the following:
(1) HNO3 acts only as an oxidising agent while HNO2 can act both as a
reducing agent and an oxidising agent.
(2) Chlorine liberates iodine from KI solution.
(1) Sodium acetate to methane
(1) S in Na2S4 O6