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## <div>Write in the simplest form:<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=a97a683197b995b4b6f1a462c6a71127.png" alt="begin mathsize 20px style space tan to the power of negative 1 end exponent space open square brackets space 1 bevelled fraction numerator space over denominator space root index blank of space x squared minus 1 end root end fraction close square brackets comma open vertical bar space x close vertical bar greater than 1 end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 6:58 PM
Answered by Expert

## <div>Solve:<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=d918d211d8c30eb0035ae182b814520d.png" alt="begin mathsize 20px style space open square brackets space 3 tan to the power of negative 1 end exponent space fraction numerator space 1 over denominator space 2 plus square root of space 3 end root end fraction close square brackets minus tan to the power of negative 1 end exponent space bevelled fraction numerator space 1 over denominator x equals tan begin display style bevelled fraction numerator blank to the power of negative 1 end exponent 1 over denominator 3 end fraction end style end fraction end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 7:05 PM
Answered by Expert

## <div>Solve:<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=bed5c13bce13a979336f34494735b43d.png" alt="begin mathsize 20px style space sin to the power of negative 1 end exponent x plus sin to the power of negative 1 end exponent y equals fraction numerator 2 straight pi over denominator 3 end fraction space comma space cos to the power of negative 1 end exponent x minus cos to the power of negative 1 end exponent y equals straight pi over 3 end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 7:10 PM
Answered by Expert

## <div>Prove that&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=442c28ac67d89906dbcb6dfd5b60787f.png" alt="begin mathsize 20px style tan to the power of negative 1 end exponent open parentheses 1 third tan 2 A close parentheses plus tan to the power of negative 1 end exponent open parentheses c o t A close parentheses plus tan to the power of negative 1 end exponent open parentheses c o t cubed A close parentheses equals 0 end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 7:20 PM
Answered by Expert

## <div>Prove that&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=c653fa6a5089719dcc9bbad99e7a56ec.png" alt="begin mathsize 20px style sin open curly brackets tan to the power of negative 1 end exponent open square brackets fraction numerator 1 minus x squared over denominator 2 x end fraction close square brackets plus cos to the power of negative 1 end exponent open square brackets fraction numerator 1 minus x squared over denominator 1 plus x squared end fraction close square brackets close curly brackets equals 1 end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 7:31 PM
Answered by Expert

## <div>Prove that&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=a86adc2d2639fa62ecade3baf7e142d1.png" alt="begin mathsize 20px style 2 tan to the power of negative 1 end exponent open parentheses bevelled 1 fifth close parentheses plus s e c to the power of negative 1 end exponent open parentheses 5 bevelled fraction numerator square root of 2 over denominator 7 end fraction close parentheses plus 2 tan to the power of negative 1 end exponent open parentheses bevelled 1 over 8 close parentheses equals bevelled straight pi over 4 end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 7:37 PM
Answered by Expert

## <div>Solve&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=7df124ba27a290e8b81bc642e8123d76.png" alt="begin mathsize 20px style tan to the power of negative 1 end exponent open parentheses 2 x close parentheses plus tan to the power of negative 1 end exponent open parentheses 3 x close parentheses equals bevelled straight pi over 4 end style" align="middle" /></div>

Asked by sunil2791 21st April 2017 7:43 PM
Answered by Expert

## Tan1/2[sin^-1 2x/1+x^2+cos^-1 1-y^2/1+y^2]=x+y/1-xy,if |x|<1,Y>0 and xy>1.

Asked by Balbir 28th April 2017 5:45 PM
Answered by Expert

## cos(2cos^-1 x +sin^-1 x) at x=1/5, 0<= cos^-1 x <=pi and -pi/2<=sin^-1 x<=pi/2.

Asked by Balbir 30th April 2017 9:28 AM
Answered by Expert

## <div>Solve the following equations &nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=70cf33911b834e50e0746c958265e814.png" alt="2 tan to the power of negative 1 space end exponent space left parenthesis cos space x right parenthesis equals space tan to the power of negative 1 end exponent space left parenthesis 2 space cos e c space x right parenthesis" align="middle" /></div>

Asked by Anshul 26th May 2017 6:14 PM
Answered by Expert

## <div>&nbsp;Solve the following equation&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=a9b0e48e93f19b894b00096c3d3b8ba0.png" alt="tan to the power of negative 1 end exponent space 1 minus x divided by 1 plus x space equals 1 divided by 2 tan to the power of negative 1 end exponent space x" align="middle" /></div>

Asked by Anshul 26th May 2017 6:22 PM
Answered by Expert

## What is Sin-1 or sin inverse state?

Asked by Shrivatsa 26th October 2017 12:21 PM
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## Arccot(sq.root cosa)+Arctan(sq.root cosa) equal to X than find the value of sinX

Asked by sudheerkapoor67 10th November 2017 3:55 AM
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## Kindly explain your answer.

Asked by Varsneya Srinivas 9th February 2018 9:07 AM
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## Can you provide a shorter solution to this question

Asked by Varsneya Srinivas 21st February 2018 10:46 AM
Answered by Expert

## pls

Asked by Singhindra038 16th April 2018 9:49 PM
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## sec-1{sec(-7pie/3)}

Asked by rajkumarrawani920 11th August 2018 10:22 AM
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## Integration ex[( 1 – x2)1/2 sin-1x + 1]/( 1 – x2)1/2 dx  explain in great detail

Asked by haroonrashidgkp 24th October 2018 8:05 PM
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