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CBSE Class 11-science Answered

Can you provide a shorter solution to this question   
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Asked by Varsneya Srinivas | 21 Feb, 2018, 10:46: AM
answered-by-expert Expert Answer
begin mathsize 16px style xy plus yz plus zx equals 1 If space you space take space straight x equals tanA comma space straight y equals tanB comma space straight z equals tanC space then tan space open parentheses straight A plus straight B plus straight C close parentheses equals tan open square brackets open parentheses straight A plus straight B close parentheses plus straight C close square brackets equals fraction numerator tan left parenthesis straight A plus straight B right parenthesis plus tanC over denominator 1 minus tan left parenthesis straight A plus straight B right parenthesis tanC end fraction Using space formula space again space for space tan left parenthesis straight A plus straight B right parenthesis you space get fraction numerator tanA plus tanB plus tanC minus tanAtanBtanC over denominator 1 minus tanAtanB minus tanBtanC minus tanAtanC end fraction as space xy plus yz plus zx equals 1 rightwards double arrow tanAtanB plus tanBtanC plus tanAtanC equals 1 rightwards double arrow tan space open parentheses straight A plus straight B plus straight C close parentheses equals infinity straight A plus straight B plus straight C space is space multiple space of space straight pi over 2 tan 2 straight A plus tan 2 straight B plus tan 2 straight C equals tan 2 straight A plus tan 2 straight B plus tan 2 straight C tan 2 straight x equals fraction numerator 2 tanx over denominator 1 minus tan squared straight x end fraction Using space this space formula space you space can space prove space it. space end style
Answered by Sneha shidid | 21 Feb, 2018, 11:23: AM

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CBSE 11-science - Maths
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