how shall i solve this numerical?please help!
Asked by pukai7229
15th May 2018,
10:24 AM
Answered by Expert
Answer:
Acceleration a produced by 5 N force on these two blocks which are in contact is given by
a = 5/(20+10) = 1/6 m/s2
20 kg block will push the 10 kg block with force F = 20×(1/6) = (10/3) N
if the force applied from other side on 10 kg block, acceleration will be same.
hence 10 kg block will push the 20 kg block with force = 10×(1/6) = (5/3)N
Answered by Expert
15th May 2018,
2:00 PM
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