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Maharashtra Class 10 Answered

formula for hypermetropia
Asked by manjurawal754 | 11 Feb, 2021, 08:00: PM
answered-by-expert Expert Answer
Let x be the distance of the near point N for the defective eye. Now the near point N' of the normal eye is at a distance D=25cm. The object placed at N' forms its 
virtual image at N due to convex lens
u=-D, v=-x f=?
1 over f equals 1 over v minus 1 over u
1 over f equals fraction numerator 1 over denominator negative x end fraction minus fraction numerator 1 over denominator negative D end fraction
f equals fraction numerator x D over denominator X minus D end fraction
P equals 1 over f
P equals fraction numerator X minus D over denominator X D end fraction 
Answered by Utkarsh Lokhande | 19 Feb, 2021, 10:38: AM
Maharashtra 10 - Science
Asked by manjurawal754 | 11 Feb, 2021, 08:00: PM
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