ICSE Class 6 Answered
Determine the number nearest to 1100000 but greater than 100000 which is exactly divisible by each of 8 15 and 21
Asked by seemarathore931 | 15 Aug, 2021, 03:18: PM
Expert Answer
8 = 2 × 2 × 2
15 = 3 × 5
21 = 3 × 7
LCM(8, 15, 21)
= 2 × 2 × 2 × 3 × 5 × 7
= 840
1100000/840--> remainder =440
nearest number = 1100000-440 = 1099560
Answered by Arun | 16 Aug, 2021, 08:42: AM
Concept Videos
-
Introduction to Fractions
This video explains the concepts of types of fractions : Unit fractions, Li... -
Addition of Fractions
This video explains the concepts of addition of fractions with same denomin... -
Introduction to Integers
Review of counting and whole numbers, evolution of integers, integers in re... -
Solving Simple Equations
Solution of Simple linear equations in one variable using hit and trail and... -
Construction of Parallel Lines
Construction of parallel lines using ruler and compass, setsquare
ICSE 6 - Maths
Asked by shergillbaljeetkaur547 | 07 Apr, 2024, 07:53: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by baibhanu157 | 16 Mar, 2024, 08:47: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by anand.kyatham | 10 Mar, 2024, 03:22: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by kalyanikirank1990 | 09 Mar, 2024, 03:05: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by sureshkumar19804g | 25 Feb, 2024, 07:55: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by sanarkhanna | 25 Feb, 2024, 10:28: AM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by southcosuprava | 11 Feb, 2024, 08:12: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by hridyanshdixit6 | 07 Feb, 2024, 09:55: PM
ANSWERED BY EXPERTICSE 6 - Maths
Asked by bosearunima | 21 Jan, 2024, 08:52: PM
ANSWERED BY EXPERT
