ICSE Class 6 Answered
A uniform plank of a sea said 5 m long supported as its center . A boy weighing 40 kgf sits at a distance of 1 m from the fulcrum. Where must a girl weighing 25 kgf sits, so as to balance the plank?
Asked by Deepnandy73 | 06 Nov, 2019, 09:02: PM
Expert Answer
A boy is sitting at a distance of 1.5 m from one end.
Plank of see-saw is 5 m long.
The fulcrum of the see saw will be exactly at centre of plank i.e. 2.5 m
Thus, load arm is 2.5 - 1.5 = 1m
Thus,
Load arm x load = effort arm x effort
1 x 40 = EA x 25
Thus,
EA = 1.6 m
Thus, the distance at which a girl must sit from other end is = 2.5 - Effort arm = 2.5 - 1.6 = 0.9 m
Answered by Shiwani Sawant | 07 Nov, 2019, 07:08: PM
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