JEE Plances Class Answered
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Asked by rbhatt16 | 14 Oct, 2017, 20:52: PM
The center of mass of the figure can be found as follows
![begin mathsize 12px style straight A open parentheses fraction numerator square root of 3 over denominator straight a end fraction straight a comma 0 close parentheses space comma space straight B open parentheses 0 comma straight a divided by 2 close parentheses space comma space straight C left parenthesis 0 comma space minus straight a divided by 2 right parenthesis
for space centre space of space mass space straight D left parenthesis straight x comma straight y right parenthesis
straight x equals fraction numerator fraction numerator square root of 3 over denominator straight a end fraction straight a plus 0 plus 0 over denominator 3 end fraction
straight y equals fraction numerator 0 plus begin display style straight a over 2 end style minus begin display style straight a over 2 end style over denominator 3 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/3ea08271f1e8b316374295fd4395207a.png)
Answered by Gajendra | 05 Dec, 2017, 19:19: PM
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