# CBSE Class 9 Maths Perpendicular From Centre to Chord

Perpendicular from centre of a circle bisects the chord.

Line segment joining the centre of a circle to the midpoint of a chord is perpendicular to the chord.

The perpendicular bisectors of two chords of a circle intersect at its centre.

There is one and only one circle which passes through 3 non-collinear points.

## Next Videos

- two circles of radii 5cm and 3cm intersect at two points and distance between the centres is 4cm. find the length of the common chord
- AC is the diameter of the circle whose centre is O .AB and CD are parallel chords of a circle .prove that OA = OB
- Q. Out of two concentric circles,the radius of the outer circle is 5 cm and the chord AC of length 8 cm is tangent to the inner circle.Find the radius of the inner circle.
- Prove that the line joining the mid points of two parallel chords of a circle, passes through the centre of the circle.
- Prove that the perpendicular from the centre of the circle to a chord bisects the chord.
- AB and CD are two parallel chords of a circle such that AB = 12 cm and CD = 24 cm. The chords are on the opposite sides of the centre and the distance between them is 17 cm. Find the distance between them.
- In a circle of radius 5 cm, AB and CD are two parallel chords of lengths 8 cm and 6 cm respectively. Find the distance between the chords if they are (i) on the same side of the centre. (ii) on the opposite sides of the centre.
- In the given figure, the diameter CD of a circle with centre O is perpendicular to chord AB. If AB = 12 cm and CE = 3 cm, find the radius of the circle.
- Show that there is one and only one circle passing through three non-collinear points.

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