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# CBSE Class 10 Answered

What is the last 3 digit number of the following Arithematic progression AP- 99,108,117
Asked by durgavenugopal70 | 28 Aug, 2019, 10:22: PM
Expert Answer

Here d = 9 and a = 99
We know that the greatest 3 digit number is 999.
Let an = 999
→an   = a + (n - 1)d
→999 = 99 + (n - 1)9
→100 = n - 1
→   n  = 101
There 101th term is 999.
Answered by Yasmeen Khan | 29 Aug, 2019, 10:55: AM

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