Two cylindrical vessels fitted with pistons A and B of area of cross section 8cm2 and 320cm2respectively,are joined at their bottom by a tube and they are completely filled with water.When a mass of 4kg is placed on piston A,find (i)  the pressure on piston A,(ii)  the pressure on piston B,and (iii)  the thrust on piston B.

Asked by saif | 14th Mar, 2017, 11:30: PM

Expert Answer:

Given that the force applied to the smaller piston A is 4 kg
Area of cross section of piston A = 8 cm²
Area of cross section of piston B = 320 cm²
begin mathsize 14px style left parenthesis straight i right parenthesis space Pressure space acting space on space piston space straight A space in space the space downward space direction space equals space Thrust over Area space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 4 space kg over denominator 8 space cm ² end fraction
therefore space Pressure space acting space on space piston space straight A equals space 0.5 space kg space cm to the power of negative 2 end exponent
left parenthesis ii right parenthesis space According space to space Pascal apostrophe straight s space Law
space Pressure space acting space on space piston space straight B space equals space Pressure space acting space on space piston space straight A space space equals space 0.5 space kg space cm to the power of negative 2 end exponent
left parenthesis iii right parenthesis Thrust space acting space on space piston space straight B space in space the space upward space direction space equals space Pressure space straight x space Area space of space straight B
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 4 space kg space straight x space fraction numerator 320 space cm ² over denominator 8 space cm ² end fraction
therefore Thrust space acting space on space piston space straight B space in space the space upward space direction space equals space 160 space kg space space
end style

Answered by Yashvanti Jain | 15th Mar, 2017, 11:56: AM