ICSE Class 9 Answered
Show that the rate of change of momentum =mass×acceleration.
Under what conditions does this relation hold?
Asked by chirgunbn | 10 May, 2020, 09:30: AM
![M o m e n t u m space i s space g i v e n space b y
space m a s s cross times v e l o c i t y
p equals m v
R a t e space o f space c h a n g e space o f space m o m e n t u m equals fraction numerator p subscript f minus p subscript i over denominator t end fraction space
R a t e space o f space c h a n g e space o f space m o m e n t u m equals fraction numerator m v subscript f minus m v subscript i over denominator t end fraction space
R a t e space o f space c h a n g e space o f space m o m e n t u m equals fraction numerator m left parenthesis v subscript f minus v subscript i right parenthesis over denominator t end fraction space
A n d space fraction numerator left parenthesis v subscript f minus v subscript i right parenthesis over denominator t end fraction equals a c c e l e r a t i o n
T h e r e f o r e space
R a t e space o f space c h a n g e space o f space m o m e n t u m equals m a
R a t e space o f space c h a n g e space o f space m o m e n t u m equals F o r c e](https://images.topperlearning.com/topper/tinymce/cache/bc35c922cffcb64cd1cbe1fb81513c84.png)
This law is valid under constant mass system.
Answered by Utkarsh Lokhande | 10 May, 2020, 10:55: AM
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