# CBSE Class 9 Answered

**please answer this question**

Draw a quadrilateral ABCD.

Mark the mid points P,Q,R and S as given in the question.

Now,

PS is parallel to and half of BD.

Simly, QR is parallel to and half of BD.

So, PS=QR

Thus, PQRS is a parallelogram ( one pair of oposite sides is parallel and equal)

Remember that diagonals of a rhombus bisect each other at right angles?

So,angle AOB is 90 degrees.

Mark the intersection of PS with AC as H and PQ with BD as G.

PS is parallel to BD , so PH is parallel to GO.

Also,

PQ is parallel to AC, so PG is parallel to HO.

So, PGOH is a parallelogram (both pairs of opposite sides are parallel)

angle O is a right angle(proved before)

So , angle HPG is also a right angle(opposite angles of a parallelogram are equal)

Thus, PQRS is a parallelogram with one angle as a right angle, so by definition of a rectangle, PQRS becomes a rectangle.